Chapter IV.1: Regular matrices
Relating to first step analysis
- One very important "first step" problem is the stationary
distribution.
- Under sutiable regularity conditions the stationary distribution
instead of being a matrix is just a vector.
- What are these magic conditions?
Regular transition matrices
- regular: P to a large power has only positive elements
- Note: thus there is an epsilon such that Pt >
epsilon for all large t.
- Via first step analysis: If we check for power n, we can show
for power n+1.
- Claim: Probability of going from i to j at some point in time is 1.
(called recurence)
- Proof: (1 - epsilon)t - - > zero.
Limiting distribution
- Pijt -->
Pijinfinity
- But does it really depend on i?
- We will use the "long run mean fraction" of times in state j
starting from state i as our probability of interest.
- Let fj(t) be the actual fraction of times in state j if
we start in state i. (NOTE: this is a random variable.)
- Let gkj(t) be the actual fraction of times in state
j AFTER we touch state k.
- Let Tk be the first time we touch k.
- Then: t fj(t) < t gj(t) + Tk
- And: t fj(t) > t gj(t)
- But: gkj(t) --> Pkjinfinity
- But: fj(t) --> Pijinfinity
- So Pkjinfinity = Pijinfinity
- Call it pij
Powers of matrices
- Computing pinfinity by computer: keep squaring it.
- For regularity: we only need to know 0*x = 0, x*y > 0.
- Keep track of signs.
- If you raise it to power larger than n2, it will be
regular if it is ever going to be regular. (proof by
induction.)
- Need all n squared steps. (Consider cyclic shift with one
alternate path of length 1 vs length 2.)
What if it isn't regular?
- One case we have already studied: absorbing states. (Note:
dependence on initial condition.)
- Another is periodic (Note: dependence on initional conditions.)
- We'll discuss both of these later in the chapter.
Dean P. Foster
Last modified: Thu Mar 5 12:42:09 EST 2009